4(u/4+3)=(u/3)4

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Solution for 4(u/4+3)=(u/3)4 equation: 



4(u/4+3)=(u/3)4

We move all terms to the left:

4(u/4+3)-((u/3)4)=0

We add all the numbers together, and all the variables

4(u/4+3)-((+u/3)4)=0

We multiply parentheses

4u-((+u/3)4)+12=0

We multiply all the terms by the denominator


4u*3)4)-((+u+12*3)4)=0

We add all the numbers together, and all the variables

4u*3)4)-((u+36)4)=0

We add all the numbers together, and all the variables

4u*3)4)-((u=0

Wy multiply elements

12u^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{0}{24}=0$

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