4(v+1)+v=5(v+3)

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Solution for 4(v+1)+v=5(v+3) equation: 



4(v+1)+v=5(v+3)

We move all terms to the left:

4(v+1)+v-(5(v+3))=0

We add all the numbers together, and all the variables

v+4(v+1)-(5(v+3))=0

We multiply parentheses

v+4v-(5(v+3))+4=0



We calculate terms in parentheses: -(5(v+3)), so:

5(v+3)

We multiply parentheses

5v+15

Back to the equation:

-(5v+15)



We add all the numbers together, and all the variables

5v-(5v+15)+4=0

We get rid of parentheses

5v-5v-15+4=0

We add all the numbers together, and all the variables

-11!=0

There is no solution for this equation

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