4(v+1)+v=8(v-1)+8

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Solution for 4(v+1)+v=8(v-1)+8 equation: 



4(v+1)+v=8(v-1)+8

We move all terms to the left:

4(v+1)+v-(8(v-1)+8)=0

We add all the numbers together, and all the variables

v+4(v+1)-(8(v-1)+8)=0

We multiply parentheses

v+4v-(8(v-1)+8)+4=0



We calculate terms in parentheses: -(8(v-1)+8), so:

8(v-1)+8

We multiply parentheses

8v-8+8

We add all the numbers together, and all the variables

8v

Back to the equation:

-(8v)



We add all the numbers together, and all the variables

-3v+4=0

We move all terms containing v to the left, all other terms to the right

-3v=-4

v=-4/-3

v=1+1/3

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