4(v+1)+v=8(v-1)=6

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Solution for 4(v+1)+v=8(v-1)=6 equation: 



4(v+1)+v=8(v-1)=6

We move all terms to the left:

4(v+1)+v-(8(v-1))=0

We add all the numbers together, and all the variables

v+4(v+1)-(8(v-1))=0

We multiply parentheses

v+4v-(8(v-1))+4=0



We calculate terms in parentheses: -(8(v-1)), so:

8(v-1)

We multiply parentheses

8v-8

Back to the equation:

-(8v-8)



We add all the numbers together, and all the variables

5v-(8v-8)+4=0

We get rid of parentheses

5v-8v+8+4=0

We add all the numbers together, and all the variables

-3v+12=0

We move all terms containing v to the left, all other terms to the right

-3v=-12

v=-12/-3

v=+4

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