4(v+1)+v=8(v-1+6)

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Solution for 4(v+1)+v=8(v-1+6) equation: 



4(v+1)+v=8(v-1+6)

We move all terms to the left:

4(v+1)+v-(8(v-1+6))=0

We add all the numbers together, and all the variables

4(v+1)+v-(8(v+5))=0

We add all the numbers together, and all the variables

v+4(v+1)-(8(v+5))=0

We multiply parentheses

v+4v-(8(v+5))+4=0



We calculate terms in parentheses: -(8(v+5)), so:

8(v+5)

We multiply parentheses

8v+40

Back to the equation:

-(8v+40)



We add all the numbers together, and all the variables

5v-(8v+40)+4=0

We get rid of parentheses

5v-8v-40+4=0

We add all the numbers together, and all the variables

-3v-36=0

We move all terms containing v to the left, all other terms to the right

-3v=36

v=36/-3

v=-12

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