4(v+1)-7=3(v-1)+v

Solution for 4(v+1)-7=3(v-1)+v equation:

Simplifying
4(v + 1) + -7 = 3(v + -1) + v

Reorder the terms:
4(1 + v) + -7 = 3(v + -1) + v
(1 * 4 + v * 4) + -7 = 3(v + -1) + v
(4 + 4v) + -7 = 3(v + -1) + v

Reorder the terms:
4 + -7 + 4v = 3(v + -1) + v

Combine like terms: 4 + -7 = -3
-3 + 4v = 3(v + -1) + v

Reorder the terms:
-3 + 4v = 3(-1 + v) + v
-3 + 4v = (-1 * 3 + v * 3) + v
-3 + 4v = (-3 + 3v) + v

Combine like terms: 3v + v = 4v
-3 + 4v = -3 + 4v

Add '3' to each side of the equation.
-3 + 3 + 4v = -3 + 3 + 4v

Combine like terms: -3 + 3 = 0
0 + 4v = -3 + 3 + 4v
4v = -3 + 3 + 4v

Combine like terms: -3 + 3 = 0
4v = 0 + 4v
4v = 4v

Add '-4v' to each side of the equation.
4v + -4v = 4v + -4v

Combine like terms: 4v + -4v = 0
0 = 4v + -4v

Combine like terms: 4v + -4v = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.