4(v+1)=8(v-1)+6

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Solution for 4(v+1)=8(v-1)+6 equation: 



4(v+1)=8(v-1)+6

We move all terms to the left:

4(v+1)-(8(v-1)+6)=0

We multiply parentheses

4v-(8(v-1)+6)+4=0



We calculate terms in parentheses: -(8(v-1)+6), so:

8(v-1)+6

We multiply parentheses

8v-8+6

We add all the numbers together, and all the variables

8v-2

Back to the equation:

-(8v-2)



We get rid of parentheses

4v-8v+2+4=0

We add all the numbers together, and all the variables

-4v+6=0

We move all terms containing v to the left, all other terms to the right

-4v=-6

v=-6/-4

v=1+1/2

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