4(v+2)+2=2(v+6)

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Solution for 4(v+2)+2=2(v+6) equation: 



4(v+2)+2=2(v+6)

We move all terms to the left:

4(v+2)+2-(2(v+6))=0

We multiply parentheses

4v-(2(v+6))+8+2=0



We calculate terms in parentheses: -(2(v+6)), so:

2(v+6)

We multiply parentheses

2v+12

Back to the equation:

-(2v+12)



We add all the numbers together, and all the variables

4v-(2v+12)+10=0

We get rid of parentheses

4v-2v-12+10=0

We add all the numbers together, and all the variables

2v-2=0

We move all terms containing v to the left, all other terms to the right

2v=2

v=2/2

v=1

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