4(v+2)=-3v+29

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Solution for 4(v+2)=-3v+29 equation: 



4(v+2)=-3v+29

We move all terms to the left:

4(v+2)-(-3v+29)=0

We multiply parentheses

4v-(-3v+29)+8=0

We get rid of parentheses

4v+3v-29+8=0

We add all the numbers together, and all the variables

7v-21=0

We move all terms containing v to the left, all other terms to the right

7v=21

v=21/7

v=3

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