4(v+2)=7v+35

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Solution for 4(v+2)=7v+35 equation: 



4(v+2)=7v+35

We move all terms to the left:

4(v+2)-(7v+35)=0

We multiply parentheses

4v-(7v+35)+8=0

We get rid of parentheses

4v-7v-35+8=0

We add all the numbers together, and all the variables

-3v-27=0

We move all terms containing v to the left, all other terms to the right

-3v=27

v=27/-3

v=-9

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