4(v+2)=8v-28

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Solution for 4(v+2)=8v-28 equation: 



4(v+2)=8v-28

We move all terms to the left:

4(v+2)-(8v-28)=0

We multiply parentheses

4v-(8v-28)+8=0

We get rid of parentheses

4v-8v+28+8=0

We add all the numbers together, and all the variables

-4v+36=0

We move all terms containing v to the left, all other terms to the right

-4v=-36

v=-36/-4

v=+9

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