4(v+2)=9v+33

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Solution for 4(v+2)=9v+33 equation: 



4(v+2)=9v+33

We move all terms to the left:

4(v+2)-(9v+33)=0

We multiply parentheses

4v-(9v+33)+8=0

We get rid of parentheses

4v-9v-33+8=0

We add all the numbers together, and all the variables

-5v-25=0

We move all terms containing v to the left, all other terms to the right

-5v=25

v=25/-5

v=-5

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