4(v+3)(-v-8)=0

Solution for 4(v+3)(-v-8)=0 equation:

4(v+3)(-v-8)=0

We add all the numbers together, and all the variables

4(v+3)(-1v-8)=0

We multiply parentheses ..

4(-1v^2-8v-3v-24)=0

We multiply parentheses

-4v^2-32v-12v-96=0

We add all the numbers together, and all the variables

-4v^2-44v-96=0

a = -4; b = -44; c = -96;
Δ = b2-4ac
Δ = -442-4·(-4)·(-96)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-20}{2*-4}=\frac{24}{-8}
=-3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+20}{2*-4}=\frac{64}{-8}
=-8
$