4(v+3)=-2(5v-4)+6v

Solution for 4(v+3)=-2(5v-4)+6v equation:

4(v+3)=-2(5v-4)+6v

We move all terms to the left:

4(v+3)-(-2(5v-4)+6v)=0

We multiply parentheses

4v-(-2(5v-4)+6v)+12=0


We calculate terms in parentheses: -(-2(5v-4)+6v), so:

-2(5v-4)+6v

We add all the numbers together, and all the variables

6v-2(5v-4)

We multiply parentheses

6v-10v+8

We add all the numbers together, and all the variables

-4v+8

Back to the equation:

-(-4v+8)


We get rid of parentheses

4v+4v-8+12=0

We add all the numbers together, and all the variables

8v+4=0

We move all terms containing v to the left, all other terms to the right

8v=-4

v=-4/8

v=-1/2