4(v+4)=-6(3v-1)+7v

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Solution for 4(v+4)=-6(3v-1)+7v equation: 



4(v+4)=-6(3v-1)+7v

We move all terms to the left:

4(v+4)-(-6(3v-1)+7v)=0

We multiply parentheses

4v-(-6(3v-1)+7v)+16=0



We calculate terms in parentheses: -(-6(3v-1)+7v), so:

-6(3v-1)+7v

We add all the numbers together, and all the variables

7v-6(3v-1)

We multiply parentheses

7v-18v+6

We add all the numbers together, and all the variables

-11v+6

Back to the equation:

-(-11v+6)



We get rid of parentheses

4v+11v-6+16=0

We add all the numbers together, and all the variables

15v+10=0

We move all terms containing v to the left, all other terms to the right

15v=-10

v=-10/15

v=-2/3

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