4(v+5)(-v+6)=0

Solution for 4(v+5)(-v+6)=0 equation:

4(v+5)(-v+6)=0

We add all the numbers together, and all the variables

4(v+5)(-1v+6)=0

We multiply parentheses ..

4(-1v^2+6v-5v+30)=0

We multiply parentheses

-4v^2+24v-20v+120=0

We add all the numbers together, and all the variables

-4v^2+4v+120=0

a = -4; b = 4; c = +120;
Δ = b2-4ac
Δ = 42-4·(-4)·120
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-44}{2*-4}=\frac{-48}{-8}
=+6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+44}{2*-4}=\frac{40}{-8}
=-5
$