4(v+5)+5v=29

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Solution for 4(v+5)+5v=29 equation: 



4(v+5)+5v=29

We move all terms to the left:

4(v+5)+5v-(29)=0

We add all the numbers together, and all the variables

5v+4(v+5)-29=0

We multiply parentheses

5v+4v+20-29=0

We add all the numbers together, and all the variables

9v-9=0

We move all terms containing v to the left, all other terms to the right

9v=9

v=9/9

v=1

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