4(v-1)-8=-2(-8v+3)-2v

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Solution for 4(v-1)-8=-2(-8v+3)-2v equation: 



4(v-1)-8=-2(-8v+3)-2v

We move all terms to the left:

4(v-1)-8-(-2(-8v+3)-2v)=0

We multiply parentheses

4v-(-2(-8v+3)-2v)-4-8=0



We calculate terms in parentheses: -(-2(-8v+3)-2v), so:

-2(-8v+3)-2v

We add all the numbers together, and all the variables

-2v-2(-8v+3)

We multiply parentheses

-2v+16v-6

We add all the numbers together, and all the variables

14v-6

Back to the equation:

-(14v-6)



We add all the numbers together, and all the variables

4v-(14v-6)-12=0

We get rid of parentheses

4v-14v+6-12=0

We add all the numbers together, and all the variables

-10v-6=0

We move all terms containing v to the left, all other terms to the right

-10v=6

v=6/-10

v=-3/5

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