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4(v-1)=2(2v-3)
We move all terms to the left:
4(v-1)-(2(2v-3))=0
We multiply parentheses
4v-(2(2v-3))-4=0
We calculate terms in parentheses: -(2(2v-3)), so:We get rid of parentheses
2(2v-3)
We multiply parentheses
4v-6
Back to the equation:
-(4v-6)
4v-4v+6-4=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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