4(v-1)=3v+4-2(-5v-2)

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Solution for 4(v-1)=3v+4-2(-5v-2) equation: 



4(v-1)=3v+4-2(-5v-2)

We move all terms to the left:

4(v-1)-(3v+4-2(-5v-2))=0

We multiply parentheses

4v-(3v+4-2(-5v-2))-4=0



We calculate terms in parentheses: -(3v+4-2(-5v-2)), so:

3v+4-2(-5v-2)

determiningTheFunctionDomain
3v-2(-5v-2)+4

We multiply parentheses

3v+10v+4+4

We add all the numbers together, and all the variables

13v+8

Back to the equation:

-(13v+8)



We get rid of parentheses

4v-13v-8-4=0

We add all the numbers together, and all the variables

-9v-12=0

We move all terms containing v to the left, all other terms to the right

-9v=12

v=12/-9

v=-1+1/3

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