4(v-1)=v+6-3(-3v-2)

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Solution for 4(v-1)=v+6-3(-3v-2) equation: 



4(v-1)=v+6-3(-3v-2)

We move all terms to the left:

4(v-1)-(v+6-3(-3v-2))=0

We multiply parentheses

4v-(v+6-3(-3v-2))-4=0



We calculate terms in parentheses: -(v+6-3(-3v-2)), so:

v+6-3(-3v-2)

determiningTheFunctionDomain
v-3(-3v-2)+6

We multiply parentheses

v+9v+6+6

We add all the numbers together, and all the variables

10v+12

Back to the equation:

-(10v+12)



We get rid of parentheses

4v-10v-12-4=0

We add all the numbers together, and all the variables

-6v-16=0

We move all terms containing v to the left, all other terms to the right

-6v=16

v=16/-6

v=-2+2/3

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