4(v-2)=2v+2-5(-4v-1)

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Solution for 4(v-2)=2v+2-5(-4v-1) equation: 



4(v-2)=2v+2-5(-4v-1)

We move all terms to the left:

4(v-2)-(2v+2-5(-4v-1))=0

We multiply parentheses

4v-(2v+2-5(-4v-1))-8=0



We calculate terms in parentheses: -(2v+2-5(-4v-1)), so:

2v+2-5(-4v-1)

determiningTheFunctionDomain
2v-5(-4v-1)+2

We multiply parentheses

2v+20v+5+2

We add all the numbers together, and all the variables

22v+7

Back to the equation:

-(22v+7)



We get rid of parentheses

4v-22v-7-8=0

We add all the numbers together, and all the variables

-18v-15=0

We move all terms containing v to the left, all other terms to the right

-18v=15

v=15/-18

v=-5/6

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