4(v-2)=4v+7-3(-4v-1)

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Solution for 4(v-2)=4v+7-3(-4v-1) equation: 



4(v-2)=4v+7-3(-4v-1)

We move all terms to the left:

4(v-2)-(4v+7-3(-4v-1))=0

We multiply parentheses

4v-(4v+7-3(-4v-1))-8=0



We calculate terms in parentheses: -(4v+7-3(-4v-1)), so:

4v+7-3(-4v-1)

determiningTheFunctionDomain
4v-3(-4v-1)+7

We multiply parentheses

4v+12v+3+7

We add all the numbers together, and all the variables

16v+10

Back to the equation:

-(16v+10)



We get rid of parentheses

4v-16v-10-8=0

We add all the numbers together, and all the variables

-12v-18=0

We move all terms containing v to the left, all other terms to the right

-12v=18

v=18/-12

v=-1+1/2

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