4(v-2)=7v+3-3(-5v-1)

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Solution for 4(v-2)=7v+3-3(-5v-1) equation: 



4(v-2)=7v+3-3(-5v-1)

We move all terms to the left:

4(v-2)-(7v+3-3(-5v-1))=0

We multiply parentheses

4v-(7v+3-3(-5v-1))-8=0



We calculate terms in parentheses: -(7v+3-3(-5v-1)), so:

7v+3-3(-5v-1)

determiningTheFunctionDomain
7v-3(-5v-1)+3

We multiply parentheses

7v+15v+3+3

We add all the numbers together, and all the variables

22v+6

Back to the equation:

-(22v+6)



We get rid of parentheses

4v-22v-6-8=0

We add all the numbers together, and all the variables

-18v-14=0

We move all terms containing v to the left, all other terms to the right

-18v=14

v=14/-18

v=-7/9

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