4(v-3)+2=5(v-2)-v

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Solution for 4(v-3)+2=5(v-2)-v equation:


Simplifying
4(v + -3) + 2 = 5(v + -2) + -1v

Reorder the terms:
4(-3 + v) + 2 = 5(v + -2) + -1v
(-3 * 4 + v * 4) + 2 = 5(v + -2) + -1v
(-12 + 4v) + 2 = 5(v + -2) + -1v

Reorder the terms:
-12 + 2 + 4v = 5(v + -2) + -1v

Combine like terms: -12 + 2 = -10
-10 + 4v = 5(v + -2) + -1v

Reorder the terms:
-10 + 4v = 5(-2 + v) + -1v
-10 + 4v = (-2 * 5 + v * 5) + -1v
-10 + 4v = (-10 + 5v) + -1v

Combine like terms: 5v + -1v = 4v
-10 + 4v = -10 + 4v

Add '10' to each side of the equation.
-10 + 10 + 4v = -10 + 10 + 4v

Combine like terms: -10 + 10 = 0
0 + 4v = -10 + 10 + 4v
4v = -10 + 10 + 4v

Combine like terms: -10 + 10 = 0
4v = 0 + 4v
4v = 4v

Add '-4v' to each side of the equation.
4v + -4v = 4v + -4v

Combine like terms: 4v + -4v = 0
0 = 4v + -4v

Combine like terms: 4v + -4v = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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