4(v-3)-5=-3(-8v+9)-4v

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Solution for 4(v-3)-5=-3(-8v+9)-4v equation: 



4(v-3)-5=-3(-8v+9)-4v

We move all terms to the left:

4(v-3)-5-(-3(-8v+9)-4v)=0

We multiply parentheses

4v-(-3(-8v+9)-4v)-12-5=0



We calculate terms in parentheses: -(-3(-8v+9)-4v), so:

-3(-8v+9)-4v

We add all the numbers together, and all the variables

-4v-3(-8v+9)

We multiply parentheses

-4v+24v-27

We add all the numbers together, and all the variables

20v-27

Back to the equation:

-(20v-27)



We add all the numbers together, and all the variables

4v-(20v-27)-17=0

We get rid of parentheses

4v-20v+27-17=0

We add all the numbers together, and all the variables

-16v+10=0

We move all terms containing v to the left, all other terms to the right

-16v=-10

v=-10/-16

v=5/8

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