4(v-4)-6=-6(-3v+2)-6v

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Solution for 4(v-4)-6=-6(-3v+2)-6v equation: 



4(v-4)-6=-6(-3v+2)-6v

We move all terms to the left:

4(v-4)-6-(-6(-3v+2)-6v)=0

We multiply parentheses

4v-(-6(-3v+2)-6v)-16-6=0



We calculate terms in parentheses: -(-6(-3v+2)-6v), so:

-6(-3v+2)-6v

We add all the numbers together, and all the variables

-6v-6(-3v+2)

We multiply parentheses

-6v+18v-12

We add all the numbers together, and all the variables

12v-12

Back to the equation:

-(12v-12)



We add all the numbers together, and all the variables

4v-(12v-12)-22=0

We get rid of parentheses

4v-12v+12-22=0

We add all the numbers together, and all the variables

-8v-10=0

We move all terms containing v to the left, all other terms to the right

-8v=10

v=10/-8

v=-1+1/4

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