4(v-5)=7v-35

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Solution for 4(v-5)=7v-35 equation: 



4(v-5)=7v-35

We move all terms to the left:

4(v-5)-(7v-35)=0

We multiply parentheses

4v-(7v-35)-20=0

We get rid of parentheses

4v-7v+35-20=0

We add all the numbers together, and all the variables

-3v+15=0

We move all terms containing v to the left, all other terms to the right

-3v=-15

v=-15/-3

v=+5

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