4(v-7)-2=-6(-3v+4)-2v

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Solution for 4(v-7)-2=-6(-3v+4)-2v equation: 



4(v-7)-2=-6(-3v+4)-2v

We move all terms to the left:

4(v-7)-2-(-6(-3v+4)-2v)=0

We multiply parentheses

4v-(-6(-3v+4)-2v)-28-2=0



We calculate terms in parentheses: -(-6(-3v+4)-2v), so:

-6(-3v+4)-2v

We add all the numbers together, and all the variables

-2v-6(-3v+4)

We multiply parentheses

-2v+18v-24

We add all the numbers together, and all the variables

16v-24

Back to the equation:

-(16v-24)



We add all the numbers together, and all the variables

4v-(16v-24)-30=0

We get rid of parentheses

4v-16v+24-30=0

We add all the numbers together, and all the variables

-12v-6=0

We move all terms containing v to the left, all other terms to the right

-12v=6

v=6/-12

v=-1/2

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