4(v1)+v=8(v-1)+6

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Solution for 4(v1)+v=8(v-1)+6 equation: 



4(v1)+v=8(v-1)+6

We move all terms to the left:

4(v1)+v-(8(v-1)+6)=0

We add all the numbers together, and all the variables

5v-(8(v-1)+6)=0



We calculate terms in parentheses: -(8(v-1)+6), so:

8(v-1)+6

We multiply parentheses

8v-8+6

We add all the numbers together, and all the variables

8v-2

Back to the equation:

-(8v-2)



We get rid of parentheses

5v-8v+2=0

We add all the numbers together, and all the variables

-3v+2=0

We move all terms containing v to the left, all other terms to the right

-3v=-2

v=-2/-3

v=2/3

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