4(w+1)+5=6(w+1)+w

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Solution for 4(w+1)+5=6(w+1)+w equation: 



4(w+1)+5=6(w+1)+w

We move all terms to the left:

4(w+1)+5-(6(w+1)+w)=0

We multiply parentheses

4w-(6(w+1)+w)+4+5=0



We calculate terms in parentheses: -(6(w+1)+w), so:

6(w+1)+w

We add all the numbers together, and all the variables

w+6(w+1)

We multiply parentheses

w+6w+6

We add all the numbers together, and all the variables

7w+6

Back to the equation:

-(7w+6)



We add all the numbers together, and all the variables

4w-(7w+6)+9=0

We get rid of parentheses

4w-7w-6+9=0

We add all the numbers together, and all the variables

-3w+3=0

We move all terms containing w to the left, all other terms to the right

-3w=-3

w=-3/-3

w=1

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