4(w+1)-7=3(w-1)+w

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Solution for 4(w+1)-7=3(w-1)+w equation:


Simplifying
4(w + 1) + -7 = 3(w + -1) + w

Reorder the terms:
4(1 + w) + -7 = 3(w + -1) + w
(1 * 4 + w * 4) + -7 = 3(w + -1) + w
(4 + 4w) + -7 = 3(w + -1) + w

Reorder the terms:
4 + -7 + 4w = 3(w + -1) + w

Combine like terms: 4 + -7 = -3
-3 + 4w = 3(w + -1) + w

Reorder the terms:
-3 + 4w = 3(-1 + w) + w
-3 + 4w = (-1 * 3 + w * 3) + w
-3 + 4w = (-3 + 3w) + w

Combine like terms: 3w + w = 4w
-3 + 4w = -3 + 4w

Add '3' to each side of the equation.
-3 + 3 + 4w = -3 + 3 + 4w

Combine like terms: -3 + 3 = 0
0 + 4w = -3 + 3 + 4w
4w = -3 + 3 + 4w

Combine like terms: -3 + 3 = 0
4w = 0 + 4w
4w = 4w

Add '-4w' to each side of the equation.
4w + -4w = 4w + -4w

Combine like terms: 4w + -4w = 0
0 = 4w + -4w

Combine like terms: 4w + -4w = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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