4(w+2)+3(w+1)=w+23

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Solution for 4(w+2)+3(w+1)=w+23 equation: 



4(w+2)+3(w+1)=w+23

We move all terms to the left:

4(w+2)+3(w+1)-(w+23)=0

We multiply parentheses

4w+3w-(w+23)+8+3=0

We get rid of parentheses

4w+3w-w-23+8+3=0

We add all the numbers together, and all the variables

6w-12=0

We move all terms containing w to the left, all other terms to the right

6w=12

w=12/6

w=2

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