4(w+3)=-2(7w-2)+4w

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Solution for 4(w+3)=-2(7w-2)+4w equation: 



4(w+3)=-2(7w-2)+4w

We move all terms to the left:

4(w+3)-(-2(7w-2)+4w)=0

We multiply parentheses

4w-(-2(7w-2)+4w)+12=0



We calculate terms in parentheses: -(-2(7w-2)+4w), so:

-2(7w-2)+4w

We add all the numbers together, and all the variables

4w-2(7w-2)

We multiply parentheses

4w-14w+4

We add all the numbers together, and all the variables

-10w+4

Back to the equation:

-(-10w+4)



We get rid of parentheses

4w+10w-4+12=0

We add all the numbers together, and all the variables

14w+8=0

We move all terms containing w to the left, all other terms to the right

14w=-8

w=-8/14

w=-4/7

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