4(w-3)=2(w-1)+(2w-10)

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Solution for 4(w-3)=2(w-1)+(2w-10) equation:


Simplifying
4(w + -3) = 2(w + -1) + (2w + -10)

Reorder the terms:
4(-3 + w) = 2(w + -1) + (2w + -10)
(-3 * 4 + w * 4) = 2(w + -1) + (2w + -10)
(-12 + 4w) = 2(w + -1) + (2w + -10)

Reorder the terms:
-12 + 4w = 2(-1 + w) + (2w + -10)
-12 + 4w = (-1 * 2 + w * 2) + (2w + -10)
-12 + 4w = (-2 + 2w) + (2w + -10)

Reorder the terms:
-12 + 4w = -2 + 2w + (-10 + 2w)

Remove parenthesis around (-10 + 2w)
-12 + 4w = -2 + 2w + -10 + 2w

Reorder the terms:
-12 + 4w = -2 + -10 + 2w + 2w

Combine like terms: -2 + -10 = -12
-12 + 4w = -12 + 2w + 2w

Combine like terms: 2w + 2w = 4w
-12 + 4w = -12 + 4w

Add '12' to each side of the equation.
-12 + 12 + 4w = -12 + 12 + 4w

Combine like terms: -12 + 12 = 0
0 + 4w = -12 + 12 + 4w
4w = -12 + 12 + 4w

Combine like terms: -12 + 12 = 0
4w = 0 + 4w
4w = 4w

Add '-4w' to each side of the equation.
4w + -4w = 4w + -4w

Combine like terms: 4w + -4w = 0
0 = 4w + -4w

Combine like terms: 4w + -4w = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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