4(w-3)=3(2+w)

Solution for 4(w-3)=3(2+w) equation:

4(w-3)=3(2+w)

We move all terms to the left:

4(w-3)-(3(2+w))=0

We add all the numbers together, and all the variables

4(w-3)-(3(w+2))=0

We multiply parentheses

4w-(3(w+2))-12=0


We calculate terms in parentheses: -(3(w+2)), so:

3(w+2)

We multiply parentheses

3w+6

Back to the equation:

-(3w+6)


We get rid of parentheses

4w-3w-6-12=0

We add all the numbers together, and all the variables

w-18=0

We move all terms containing w to the left, all other terms to the right

w=18