4(x+-3)+-5(x+2)=7(3x+-1)+29

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Solution for 4(x+-3)+-5(x+2)=7(3x+-1)+29 equation: 



4(x+-3)+-5(x+2)=7(3x+-1)+29

We move all terms to the left:

4(x+-3)+-5(x+2)-(7(3x+-1)+29)=0

We add all the numbers together, and all the variables

4(x-3)-5(x+2)-(7(3x-1)+29)+=0

We add all the numbers together, and all the variables

4(x-3)-5(x+2)-(7(3x-1)+29)=0

We multiply parentheses

4x-5x-(7(3x-1)+29)-12-10=0



We calculate terms in parentheses: -(7(3x-1)+29), so:

7(3x-1)+29

We multiply parentheses

21x-7+29

We add all the numbers together, and all the variables

21x+22

Back to the equation:

-(21x+22)



We add all the numbers together, and all the variables

-1x-(21x+22)-22=0

We get rid of parentheses

-1x-21x-22-22=0

We add all the numbers together, and all the variables

-22x-44=0

We move all terms containing x to the left, all other terms to the right

-22x=44

x=44/-22

x=-2

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