4(x+-3)=20

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Solution for 4(x+-3)=20 equation: 



4(x+-3)=20

We move all terms to the left:

4(x+-3)-(20)=0

We add all the numbers together, and all the variables

4(x-3)-20=0

We multiply parentheses

4x-12-20=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8

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