4(x+1)+(x+3)=5(x+1)+2

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Solution for 4(x+1)+(x+3)=5(x+1)+2 equation:


Simplifying
4(x + 1) + (x + 3) = 5(x + 1) + 2

Reorder the terms:
4(1 + x) + (x + 3) = 5(x + 1) + 2
(1 * 4 + x * 4) + (x + 3) = 5(x + 1) + 2
(4 + 4x) + (x + 3) = 5(x + 1) + 2

Reorder the terms:
4 + 4x + (3 + x) = 5(x + 1) + 2

Remove parenthesis around (3 + x)
4 + 4x + 3 + x = 5(x + 1) + 2

Reorder the terms:
4 + 3 + 4x + x = 5(x + 1) + 2

Combine like terms: 4 + 3 = 7
7 + 4x + x = 5(x + 1) + 2

Combine like terms: 4x + x = 5x
7 + 5x = 5(x + 1) + 2

Reorder the terms:
7 + 5x = 5(1 + x) + 2
7 + 5x = (1 * 5 + x * 5) + 2
7 + 5x = (5 + 5x) + 2

Reorder the terms:
7 + 5x = 5 + 2 + 5x

Combine like terms: 5 + 2 = 7
7 + 5x = 7 + 5x

Add '-7' to each side of the equation.
7 + -7 + 5x = 7 + -7 + 5x

Combine like terms: 7 + -7 = 0
0 + 5x = 7 + -7 + 5x
5x = 7 + -7 + 5x

Combine like terms: 7 + -7 = 0
5x = 0 + 5x
5x = 5x

Add '-5x' to each side of the equation.
5x + -5x = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 5x + -5x

Combine like terms: 5x + -5x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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