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4(x+1)+12=2(x+3)+10
We move all terms to the left:
4(x+1)+12-(2(x+3)+10)=0
We multiply parentheses
4x-(2(x+3)+10)+4+12=0
We calculate terms in parentheses: -(2(x+3)+10), so:We add all the numbers together, and all the variables
2(x+3)+10
We multiply parentheses
2x+6+10
We add all the numbers together, and all the variables
2x+16
Back to the equation:
-(2x+16)
4x-(2x+16)+16=0
We get rid of parentheses
4x-2x-16+16=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0
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