4(x+1)+2(x+I)=12

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Solution for 4(x+1)+2(x+I)=12 equation: 



4(x+1)+2(x+)=12

We move all terms to the left:

4(x+1)+2(x+)-(12)=0

We add all the numbers together, and all the variables

4(x+1)+2(+x)-12=0

We multiply parentheses

4x+2x+4-12=0

We add all the numbers together, and all the variables

6x-8=0

We move all terms containing x to the left, all other terms to the right

6x=8

x=8/6

x=1+1/3

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