4(x+1)+2(x-2)=18

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Solution for 4(x+1)+2(x-2)=18 equation: 



4(x+1)+2(x-2)=18

We move all terms to the left:

4(x+1)+2(x-2)-(18)=0

We multiply parentheses

4x+2x+4-4-18=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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