4(x+1)+2(x-2)=18

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Solution for 4(x+1)+2(x-2)=18 equation:



4(x+1)+2(x-2)=18
We move all terms to the left:
4(x+1)+2(x-2)-(18)=0
We multiply parentheses
4x+2x+4-4-18=0
We add all the numbers together, and all the variables
6x-18=0
We move all terms containing x to the left, all other terms to the right
6x=18
x=18/6
x=3

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