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4(x+1)+2(x-3)=3(x-2)+3(x-5)
We move all terms to the left:
4(x+1)+2(x-3)-(3(x-2)+3(x-5))=0
We multiply parentheses
4x+2x-(3(x-2)+3(x-5))+4-6=0
We calculate terms in parentheses: -(3(x-2)+3(x-5)), so:We add all the numbers together, and all the variables
3(x-2)+3(x-5)
We multiply parentheses
3x+3x-6-15
We add all the numbers together, and all the variables
6x-21
Back to the equation:
-(6x-21)
6x-(6x-21)-2=0
We get rid of parentheses
6x-6x+21-2=0
We add all the numbers together, and all the variables
19!=0
There is no solution for this equation
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