4(x+1)+20=3(x+1)+210

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Solution for 4(x+1)+20=3(x+1)+210 equation: 



4(x+1)+20=3(x+1)+210

We move all terms to the left:

4(x+1)+20-(3(x+1)+210)=0

We multiply parentheses

4x-(3(x+1)+210)+4+20=0



We calculate terms in parentheses: -(3(x+1)+210), so:

3(x+1)+210

We multiply parentheses

3x+3+210

We add all the numbers together, and all the variables

3x+213

Back to the equation:

-(3x+213)



We add all the numbers together, and all the variables

4x-(3x+213)+24=0

We get rid of parentheses

4x-3x-213+24=0

We add all the numbers together, and all the variables

x-189=0

We move all terms containing x to the left, all other terms to the right

x=189

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