4(x+1)+20=3(x+1)+210

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Solution for 4(x+1)+20=3(x+1)+210 equation:



4(x+1)+20=3(x+1)+210
We move all terms to the left:
4(x+1)+20-(3(x+1)+210)=0
We multiply parentheses
4x-(3(x+1)+210)+4+20=0
We calculate terms in parentheses: -(3(x+1)+210), so:
3(x+1)+210
We multiply parentheses
3x+3+210
We add all the numbers together, and all the variables
3x+213
Back to the equation:
-(3x+213)
We add all the numbers together, and all the variables
4x-(3x+213)+24=0
We get rid of parentheses
4x-3x-213+24=0
We add all the numbers together, and all the variables
x-189=0
We move all terms containing x to the left, all other terms to the right
x=189

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