4(x+1)+2c=7+3(x-1)

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Solution for 4(x+1)+2c=7+3(x-1) equation:


Simplifying
4(x + 1) + 2c = 7 + 3(x + -1)

Reorder the terms:
4(1 + x) + 2c = 7 + 3(x + -1)
(1 * 4 + x * 4) + 2c = 7 + 3(x + -1)
(4 + 4x) + 2c = 7 + 3(x + -1)

Reorder the terms:
4 + 2c + 4x = 7 + 3(x + -1)

Reorder the terms:
4 + 2c + 4x = 7 + 3(-1 + x)
4 + 2c + 4x = 7 + (-1 * 3 + x * 3)
4 + 2c + 4x = 7 + (-3 + 3x)

Combine like terms: 7 + -3 = 4
4 + 2c + 4x = 4 + 3x

Add '-4' to each side of the equation.
4 + 2c + -4 + 4x = 4 + -4 + 3x

Reorder the terms:
4 + -4 + 2c + 4x = 4 + -4 + 3x

Combine like terms: 4 + -4 = 0
0 + 2c + 4x = 4 + -4 + 3x
2c + 4x = 4 + -4 + 3x

Combine like terms: 4 + -4 = 0
2c + 4x = 0 + 3x
2c + 4x = 3x

Solving
2c + 4x = 3x

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4x' to each side of the equation.
2c + 4x + -4x = 3x + -4x

Combine like terms: 4x + -4x = 0
2c + 0 = 3x + -4x
2c = 3x + -4x

Combine like terms: 3x + -4x = -1x
2c = -1x

Divide each side by '2'.
c = -0.5x

Simplifying
c = -0.5x

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