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4(x+1)+3(x+4)=12
We move all terms to the left:
4(x+1)+3(x+4)-(12)=0
We multiply parentheses
4x+3x+4+12-12=0
We add all the numbers together, and all the variables
7x+4=0
We move all terms containing x to the left, all other terms to the right
7x=-4
x=-4/7
x=-4/7
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