4(x+1)+3(x-2)=19

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Solution for 4(x+1)+3(x-2)=19 equation: 



4(x+1)+3(x-2)=19

We move all terms to the left:

4(x+1)+3(x-2)-(19)=0

We multiply parentheses

4x+3x+4-6-19=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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