4(x+1)+3(x-3)=2

Solution for 4(x+1)+3(x-3)=2 equation:

Simplifying
4(x + 1) + 3(x + -3) = 2

Reorder the terms:
4(1 + x) + 3(x + -3) = 2
(1 * 4 + x * 4) + 3(x + -3) = 2
(4 + 4x) + 3(x + -3) = 2

Reorder the terms:
4 + 4x + 3(-3 + x) = 2
4 + 4x + (-3 * 3 + x * 3) = 2
4 + 4x + (-9 + 3x) = 2

Reorder the terms:
4 + -9 + 4x + 3x = 2

Combine like terms: 4 + -9 = -5
-5 + 4x + 3x = 2

Combine like terms: 4x + 3x = 7x
-5 + 7x = 2

Solving
-5 + 7x = 2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 7x = 2 + 5

Combine like terms: -5 + 5 = 0
0 + 7x = 2 + 5
7x = 2 + 5

Combine like terms: 2 + 5 = 7
7x = 7

Divide each side by '7'.
x = 1

Simplifying
x = 1