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4(x+1)+3=2x+2(3+x)
We move all terms to the left:
4(x+1)+3-(2x+2(3+x))=0
We add all the numbers together, and all the variables
4(x+1)-(2x+2(x+3))+3=0
We multiply parentheses
4x-(2x+2(x+3))+4+3=0
We calculate terms in parentheses: -(2x+2(x+3)), so:We add all the numbers together, and all the variables
2x+2(x+3)
We multiply parentheses
2x+2x+6
We add all the numbers together, and all the variables
4x+6
Back to the equation:
-(4x+6)
4x-(4x+6)+7=0
We get rid of parentheses
4x-4x-6+7=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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