4(x+1)+5=6(x-1)+1

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Solution for 4(x+1)+5=6(x-1)+1 equation: 



4(x+1)+5=6(x-1)+1

We move all terms to the left:

4(x+1)+5-(6(x-1)+1)=0

We multiply parentheses

4x-(6(x-1)+1)+4+5=0



We calculate terms in parentheses: -(6(x-1)+1), so:

6(x-1)+1

We multiply parentheses

6x-6+1

We add all the numbers together, and all the variables

6x-5

Back to the equation:

-(6x-5)



We add all the numbers together, and all the variables

4x-(6x-5)+9=0

We get rid of parentheses

4x-6x+5+9=0

We add all the numbers together, and all the variables

-2x+14=0

We move all terms containing x to the left, all other terms to the right

-2x=-14

x=-14/-2

x=+7

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